Observe the figure below and find the area of trapezium PQRS.

Correct option is D

Given:

Formula Used:

Area of trapezium = $$\frac{1}{2} \times (sum \ of \ parallel \ sides) \times height$$ 

Solution:  

PQR is a right angle triangle 

BY Pythagoras Theorem   

$$(QR)^2 = (PR)^2 - (PQ)^2 \\\ = (15)^2 - (9)^2 \\\ = 225 - 81 \\\ = 144$$​   

QR = 12 cm

QR is the height of the trapezium 

Then the area of the trapezium   = $$\frac{1}{2} \times (sum \ of \ parallel \ sides) \times height$$   

=    $$\frac{1}{2} \times (9 + 8 ) \times 12$$ 

= 102 cm²​