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The difference between the lengths of two parallel sides of a trapezium is 6 cm. The perpendicular distance between them is 24 cm. If the area of the
Question

The difference between the lengths of two parallel sides of a trapezium is 6 cm. The perpendicular distance between them is 24 cm. If the area of the trapezium is 648 cm2, then what is the length of the parallel sides?​

A.

28 cm, 22 cm

B.

30 cm, 24 cm

C.

36 cm, 30 cm

D.

23 cm, 29 cm

Correct option is B

Given:

Difference between the lengths of two parallel sides of a trapezium = 6 cm

Perpendicular distance (height) = 24 cm

Area of the trapezium = 648 cm²

Find the lengths of the parallel sides.

Formula Used:

Area of a trapezium = 12\frac{1}{2}​ × sum of parallel sides× height

Solution:

Let the parallel sides be x cm and x + 6 cm

Using the area formula:

648 = 12×(x+x+6)×24 \frac{1}{2} \times (x + x + 6) \times 24​​

648 = 12(2x + 6)

648 = 24x + 72

24x = 576

x = 24

So, the lengths of the parallel sides are: 24 cm and 30 cm

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