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    The difference between the lengths of two parallel sides of a trapezium is 6 cm. The perpendicular distance between them is 24 cm. If the area of the
    Question

    The difference between the lengths of two parallel sides of a trapezium is 6 cm. The perpendicular distance between them is 24 cm. If the area of the trapezium is 648 cm2, then what is the length of the parallel sides?​

    A.

    28 cm, 22 cm

    B.

    30 cm, 24 cm

    C.

    36 cm, 30 cm

    D.

    23 cm, 29 cm

    Correct option is B

    Given:

    Difference between the lengths of two parallel sides of a trapezium = 6 cm

    Perpendicular distance (height) = 24 cm

    Area of the trapezium = 648 cm²

    Find the lengths of the parallel sides.

    Formula Used:

    Area of a trapezium = 12\frac{1}{2}​ × sum of parallel sides× height

    Solution:

    Let the parallel sides be x cm and x + 6 cm

    Using the area formula:

    648 = 12×(x+x+6)×24 \frac{1}{2} \times (x + x + 6) \times 24​​

    648 = 12(2x + 6)

    648 = 24x + 72

    24x = 576

    x = 24

    So, the lengths of the parallel sides are: 24 cm and 30 cm

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