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    A field is in the shape of a trapezium, whose parallel sides measure 250 m and 110 m and non-parallel sides measure 150 m and 130 m. What is the area
    Question

    A field is in the shape of a trapezium, whose parallel sides measure 250 m and 110 m and non-parallel sides measure 150 m and 130 m. What is the area (in hectares) of the field?

    A.

    2.16

    B.

    2.12

    C.

    2.54

    D.

    3.24

    Correct option is A

    Given:

    Parallel sides of trapezium = 250 m and 110 m

    Non-parallel sides = 150 m and 130 m

    Formula Used:

    Semi perimeter of triangle = a+b+c2\frac{a+b+c}{2}​​

    Area of triangle = s(sa)(sb)(sc)\sqrt{s(s-a)(s-b)(s-c)}

    ​​Area of triangle = 12×Base×Height\frac{1}{2} \times \text{Base} \times \text{Height}​​

    Area of trapezium = 12×(sum of parallel sides)×\frac{1}{2} \times (\text{sum of parallel sides}) \times​ height

    1 hectare = 10,000 square meters

    Solution:

    Semi perimeter of triangle (S) = 130+150+1402\frac{130 + 150 + 140}{2} = 210 m

    Area of triangle = 210(210130)(210150)(210140)\sqrt{210(210 - 130) (210 - 150) (210 -140)} 

    = 210(80)(60)(70)\sqrt{210(80) (60) (70)}​​

    3×70×16×5×70×12×5\sqrt{3 \times 70 \times 16 \times 5 \times 70 \times 12 \times 5}

    = 70 ×\times 4 ×\times 5 ×\times 6

    = 8400 m2 

    Now, By Area of triangle formula:  

    8400 = 12×140×Height\frac{1}{2} \times 140 \times \text{Height}

    Height  = 8400×2140\frac{8400 \times 2}{140}

    = 120 m

    Now,

    Area of trapezium = 12×(110+250)×120\frac{1}{2} \times (110 + 250) \times 120​​

    12×(360)×120\frac{1}{2} \times (360) \times 120

    = 21600 m2

    Convert to hectares:
    = 2160010000=2.16\frac{21600}{10000} = 2.16 hectares

    Thus, the correct option is (a) 2.16 hectares


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