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A field is in the shape of a trapezium, whose parallel sides measure 250 m and 110 m and non-parallel sides measure 150 m and 130 m. What is the area
Question

A field is in the shape of a trapezium, whose parallel sides measure 250 m and 110 m and non-parallel sides measure 150 m and 130 m. What is the area (in hectares) of the field?

A.

2.16

B.

2.12

C.

2.54

D.

3.24

Correct option is A

Given:

Parallel sides of trapezium = 250 m and 110 m

Non-parallel sides = 150 m and 130 m

Formula Used:

Semi perimeter of triangle = a+b+c2\frac{a+b+c}{2}​​

Area of triangle = s(sa)(sb)(sc)\sqrt{s(s-a)(s-b)(s-c)}

​​Area of triangle = 12×Base×Height\frac{1}{2} \times \text{Base} \times \text{Height}​​

Area of trapezium = 12×(sum of parallel sides)×\frac{1}{2} \times (\text{sum of parallel sides}) \times​ height

1 hectare = 10,000 square meters

Solution:

Semi perimeter of triangle (S) = 130+150+1402\frac{130 + 150 + 140}{2} = 210 m

Area of triangle = 210(210130)(210150)(210140)\sqrt{210(210 - 130) (210 - 150) (210 -140)} 

= 210(80)(60)(70)\sqrt{210(80) (60) (70)}​​

3×70×16×5×70×12×5\sqrt{3 \times 70 \times 16 \times 5 \times 70 \times 12 \times 5}

= 70 ×\times 4 ×\times 5 ×\times 6

= 8400 m2 

Now, By Area of triangle formula:  

8400 = 12×140×Height\frac{1}{2} \times 140 \times \text{Height}

Height  = 8400×2140\frac{8400 \times 2}{140}

= 120 m

Now,

Area of trapezium = 12×(110+250)×120\frac{1}{2} \times (110 + 250) \times 120​​

12×(360)×120\frac{1}{2} \times (360) \times 120

= 21600 m2

Convert to hectares:
= 2160010000=2.16\frac{21600}{10000} = 2.16 hectares

Thus, the correct option is (a) 2.16 hectares


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