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    Find the area of a trapezium whose parallel sides have lengths of 12 cm and 18 cm respectively and the shortest distance between them is 20 cm.
    Question

    Find the area of a trapezium whose parallel sides have lengths of 12 cm and 18 cm respectively and the shortest distance between them is 20 cm.

    A.

    600 cm²

    B.

    195 cm²

    C.

    300 cm²

    D.

    210 cm²

    Correct option is C

    Given:
    The length of the parallel sides of the trapezium are 12 cm and 18 cm.
    The shortest distance between two parallel side is 20 cm.
    Concept Used:
    Area of a trapezium = 12\frac 12​ × (Sum of the length of the parallel sides) × (Shortest distance or perpendicular distance between two parallel side)
    Solution:
    Area of the trapezium = 12\frac 12​ × (12 + 18) × (20) =  15 × 20 =  300 sq. cm

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