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Find the area of a trapezium whose parallel sides have lengths of 12 cm and 18 cm respectively and the shortest distance between them is 20 cm.
Question

Find the area of a trapezium whose parallel sides have lengths of 12 cm and 18 cm respectively and the shortest distance between them is 20 cm.

A.

600 cm²

B.

195 cm²

C.

300 cm²

D.

210 cm²

Correct option is C

Given:
The length of the parallel sides of the trapezium are 12 cm and 18 cm.
The shortest distance between two parallel side is 20 cm.
Concept Used:
Area of a trapezium = 12\frac 12​ × (Sum of the length of the parallel sides) × (Shortest distance or perpendicular distance between two parallel side)
Solution:
Area of the trapezium = 12\frac 12​ × (12 + 18) × (20) =  15 × 20 =  300 sq. cm

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