The area of a trapezium is 160 sq. cm. If the lengths of the parallel sides are 20 cm and 12 cm, respectively, then the perpendicular distance (in cm) between the parallel sides is:

Correct option is A

Given:

Area of the trapezium = 160 cm²

Length of the first parallel side a=20 cm

Length of the second parallel side b=12 cm

Formula Used:

A = $$\frac{1}{2} \times (a + b) \times h$$​

where a and b are the lengths of the parallel sides, and h is the perpendicular distance (height) between them

Solution:

160 = $$\frac{1}{2} \times (20 + 12) \times h$$​

160 = $$\frac{1}{2} \times 32 \times h$$​

160 = $$16 \times h$$​

h = 10cm