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    If x² - 11x + 1 = 0, what is the value of x⁸ - 14159x⁴ + 11?
    Question

    If x² - 11x + 1 = 0, what is the value of x⁸ - 14159x⁴ + 11?

    A.

    9

    B.

    10

    C.

    12

    D.

    11

    Correct option is B

    Given:

    x^2 - 11x + 1 = 0 

    Formula Used: 

    x+1x=kx+\frac{1}{x} = k  

    x2+1x2=k22x^2 + \frac{1}{x^2} = k^2 - 2
    Solution:

    On dividing by  we get,

    =>x11+1x=0 =>x+1x=11 =>x2+1x2=(11)22 x2+1x2=119\Rightarrow x - 11 + \frac{1}{x} = 0\\\ \\\Rightarrow x + \frac{1}{x} = 11\\\ \\\Rightarrow x^2 + \frac{1}{x^2} = (11)^2 - 2\\\ \\x^2 + \frac{1}{x^2} = 119​​

    Squaring both sides

    ​​x4+1x4=141612=14159 ​​x^4 + \frac{1}{x^4} = 14161 - 2 = 14159 \\\ \\ ​​

    Then the value of  x⁸ - 14159x⁴ + 11​​


    x4(x414159)+11 x4(x4x41x4)+11 x4(1x4)+11 1+11=10x^4(x^4 - 14159) + 11\\\ \\x^4(x^4 -x^4- \frac{1}{x^4}) + 11\\\ \\x^4 \left( - \frac{1}{x^4} \right) + 11\\\ \\-1 + 11 = 10​​​
    x⁸ - 14159x⁴ + 11

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