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If x² - 11x + 1 = 0, what is the value of x⁸ - 14159x⁴ + 11?
Question

If x² - 11x + 1 = 0, what is the value of x⁸ - 14159x⁴ + 11?

A.

9

B.

10

C.

12

D.

11

Correct option is B

Given:

x^2 - 11x + 1 = 0 

Formula Used: 

x+1x=kx+\frac{1}{x} = k  

x2+1x2=k22x^2 + \frac{1}{x^2} = k^2 - 2
Solution:

On dividing by  we get,

=>x11+1x=0 =>x+1x=11 =>x2+1x2=(11)22 x2+1x2=119\Rightarrow x - 11 + \frac{1}{x} = 0\\\ \\\Rightarrow x + \frac{1}{x} = 11\\\ \\\Rightarrow x^2 + \frac{1}{x^2} = (11)^2 - 2\\\ \\x^2 + \frac{1}{x^2} = 119​​

Squaring both sides

​​x4+1x4=141612=14159 ​​x^4 + \frac{1}{x^4} = 14161 - 2 = 14159 \\\ \\ ​​

Then the value of  x⁸ - 14159x⁴ + 11​​


x4(x414159)+11 x4(x4x41x4)+11 x4(1x4)+11 1+11=10x^4(x^4 - 14159) + 11\\\ \\x^4(x^4 -x^4- \frac{1}{x^4}) + 11\\\ \\x^4 \left( - \frac{1}{x^4} \right) + 11\\\ \\-1 + 11 = 10​​​
x⁸ - 14159x⁴ + 11

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