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    If the quadratic equation ax2−4x+1=0ax^2 - 4x + 1 = 0ax2−4x+1=0 has equal roots, then the value of a is:
    Question

    If the quadratic equation ax24x+1=0ax^2 - 4x + 1 = 0 has equal roots, then the value of a is:

    A.

    2

    B.

    1

    C.

    3

    D.

    4

    Correct option is D

    Given:

    The quadratic equation is:

    ax2 - 4x + 1 = 0

    It is stated that the equation has equal roots.

    Concept Used:

    For a quadratic equation to have equal roots, the discriminant (D) must be zero. The discriminant is given by:

    D = b2 - 4ac

    Solution:

    For the equation ax2 - 4x + 1 = 0 the coefficients are:

    a = a,  b = −4, c = 1

    Substituting these into the discriminant formula:

    D = (-4)2 - 4(a)(1)

    D = 16 − 4a

    D = 0 (since roots are equal):

    16 - 4a = 0

    4a = 16 

    a = 4

    The value of a is 4.

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