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If the quadratic equation ax2−4x+1=0ax^2 - 4x + 1 = 0ax2−4x+1=0 has equal roots, then the value of a is:
Question

If the quadratic equation ax24x+1=0ax^2 - 4x + 1 = 0 has equal roots, then the value of a is:

A.

2

B.

1

C.

3

D.

4

Correct option is D

Given:

The quadratic equation is:

ax2 - 4x + 1 = 0

It is stated that the equation has equal roots.

Concept Used:

For a quadratic equation to have equal roots, the discriminant (D) must be zero. The discriminant is given by:

D = b2 - 4ac

Solution:

For the equation ax2 - 4x + 1 = 0 the coefficients are:

a = a,  b = −4, c = 1

Substituting these into the discriminant formula:

D = (-4)2 - 4(a)(1)

D = 16 − 4a

D = 0 (since roots are equal):

16 - 4a = 0

4a = 16 

a = 4

The value of a is 4.

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