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    If α and β are the zeroes of the polynomial x2−5x+mx^2-5x+mx2−5x+m​ such that α – β = 1, then what will be the value of mmm​.
    Question

    If α and β are the zeroes of the polynomial x25x+mx^2-5x+m​ such that α – β = 1, then what will be the value of mm​.

    A.

    3

    B.

    2

    C.

    6

    D.

    10

    Correct option is C

    Given:

    The polynomial is x2^2​ - 5x + m, and the roots α and β satisfy α – β = 1

    Concept Used:
    α+β=baandαβ=ca\alpha + \beta = -\frac{b}{a} \quad \text{and} \quad \alpha \beta = \frac{c}{a}

    Solution:
    α+β=51=5andαβ=m1\alpha + \beta = -\frac{-5}{1} = 5 \quad \text{and} \quad \alpha \beta = \frac{m}{1}​ = m

    α+β=5andαβ\alpha + \beta = 5 \quad \text{and} \quad \alpha \beta​ = m

    α\alpha ​ – β = 1

    (αβ)2=(α+β)24αβ(\alpha - \beta)^2 = (\alpha + \beta)^2 - 4 \alpha \beta

    12=52^2 = 5^2​ - 4m

    1 = 25 − 4m

    4m = 25 - 1

    4m = 24

    m = 6

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