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If α and β are the zeroes of the polynomial x2−5x+mx^2-5x+mx2−5x+m​ such that α – β = 1, then what will be the value of mmm​.
Question

If α and β are the zeroes of the polynomial x25x+mx^2-5x+m​ such that α – β = 1, then what will be the value of mm​.

A.

3

B.

2

C.

6

D.

10

Correct option is C

Given:

The polynomial is x2^2​ - 5x + m, and the roots α and β satisfy α – β = 1

Concept Used:
α+β=baandαβ=ca\alpha + \beta = -\frac{b}{a} \quad \text{and} \quad \alpha \beta = \frac{c}{a}

Solution:
α+β=51=5andαβ=m1\alpha + \beta = -\frac{-5}{1} = 5 \quad \text{and} \quad \alpha \beta = \frac{m}{1}​ = m

α+β=5andαβ\alpha + \beta = 5 \quad \text{and} \quad \alpha \beta​ = m

α\alpha ​ – β = 1

(αβ)2=(α+β)24αβ(\alpha - \beta)^2 = (\alpha + \beta)^2 - 4 \alpha \beta

12=52^2 = 5^2​ - 4m

1 = 25 − 4m

4m = 25 - 1

4m = 24

m = 6

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