If 5x²-8y-20x+2xy=(x+a)(bx+2y), then the value of (a-b) is:
Given:
5x^2- 8y - 20x + 2xy = (x + a)(bx + 2y)
5x^2- 8y - 20x + 2xy=bx^2 + 2xy + abx + 2ay
Comparing on both sides
b = 5 and
ab = -20
5a = -20
a = -4
we find (a-b) = -4-5 = -9
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