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Find the values of b for which the quadratic equation 4x² + bx + 1 = 0 has equal roots.
Question

Find the values of b for which the quadratic equation 4x² + bx + 1 = 0 has equal roots.

A.

​Only -4

B.

-4 and 4

C.

Only 4

D.

-8 and 8

Correct option is B

Given:

4x2+bx+1=04x^2 + bx + 1 = 0​​

Formula Used: 

In a quadratic equation
Equal roots when:

b24ac=0b^2 - 4ac = 0​​

Solution: 

4x2+bx+1=04x^2 + bx + 1 = 0
Here, a = 4, c = 1: 

So, 

b24(4)(1)=0 b2=16  b=±4b^2 - 4(4)(1) = 0 \\ \ \\ b^2 = 16 \\ \ \\ \implies b = \pm 4 ​​

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