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    Find the values of b for which the quadratic equation 4x² + bx + 1 = 0 has equal roots.
    Question

    Find the values of b for which the quadratic equation 4x² + bx + 1 = 0 has equal roots.

    A.

    ​Only -4

    B.

    -4 and 4

    C.

    Only 4

    D.

    -8 and 8

    Correct option is B

    Given:

    4x2+bx+1=04x^2 + bx + 1 = 0​​

    Formula Used: 

    In a quadratic equation
    Equal roots when:

    b24ac=0b^2 - 4ac = 0​​

    Solution: 

    4x2+bx+1=04x^2 + bx + 1 = 0
    Here, a = 4, c = 1: 

    So, 

    b24(4)(1)=0 b2=16  b=±4b^2 - 4(4)(1) = 0 \\ \ \\ b^2 = 16 \\ \ \\ \implies b = \pm 4 ​​

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