Find the sum of the roots of $$\sqrt2 x^2-2\sqrt5 x+\sqrt3=0.$$​​

Correct option is A

Given:

​$$√2 x^2-2√5 x+√3=0.$$ 

Formula used:

The sum of the root of quadratic equation $$ax^2+bx+c=0$$ which is

Sum of the roots = $$\frac{-b}{a}$$ 

Solution:

$$a$$​ = √2

$$b$$​ = -2√5

$$c$$ = √3

Substitute the values:​​

Sum of the roots = $$\frac{-b}{a}$$ = $$\frac{-(-2√5)}{\sqrt2}$$

Multiply with $$\sqrt2$$ in numerator and denominator.

​$$\frac{2√5}{\sqrt2}\times \frac{\sqrt2}{\sqrt2}= \frac{2\sqrt10}{2}= \sqrt10$$ 

Thus the correct answer is (A)

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