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A quadratic equation is given by x² − 6x + k = 0. Find the value of k for which the equation has equal real roots.
Question

A quadratic equation is given by x² − 6x + k = 0. Find the value of k for which the equation has equal real roots.

A.

5

B.

11

C.

9

D.

7

Correct option is C

Given:

Quadratic equation: x26x+kx^2 - 6x + k​ = 0;

Required: Value of k for which the equation has equal real roots.

Concept Used:

A quadratic equation has equal real roots when the discriminant D = 0

Discriminant D = b24acb^2 - 4ac​​

Solution:

Here, a = 1, b = -6, c = k

D = (-6)2 - 4(1)(k) = 36 - 4k

Now, D = 0:

36 - 4k = 0

4k = 36

k = 364\frac{36}{4}​ = 9

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