A city has a population of 10,000 people and population grows at a rate of 10% per annum. What will be the population in 3 years?

Correct option is A

Given:

Initial population (P) = 10,000 people
Growth rate = 10% per annum
Time (T) = 3 years

Formula Used:

The formula for population growth is:
​$$A = P (1 +\frac{ r}{100})^t$$​​
Where A is the population after time t, P is the initial population, r is the rate of growth per annum, and t is the time in years.

Population after 3 years = $$10,000 × (1 + \frac{10}{100})^3$$​​

Solution:

Substitute the given values into the formula:
​$$A = 10,000 × (1 + \frac{10}{100})^3 \\\ \\A = 10,000 × (1.1)^3\\\ \\A = 10,000 × 1.331 = 13,310$$​​

Thus, the population of the city after 3 years will be 13,310 people.