A bacterial population increases at the rate of 6% in the first 10 minutes and then increase 10% in the next 10 minutes. What is the overall percentage increase in the population at the end of 20 minutes?​

Correct option is D

Given:

Initial population of bacteria = P

Increase in the first 10 minutes = 6%

Increase in the next 10 minutes = 10%

Formula Used:

​$$\text{Overall Percentage Increase} = a + b + \frac{a \cdot b}{100} ​$$​​

Where a and b are the individual percentage increases.

Solution:

Here, a=6 and b=10

​$$\text{Overall Percentage Increase} = 6 + 10 + \frac{6 \cdot 10}{100}$$

$$\text{Overall Percentage Increase} = 6 + 10 + 0.6 = 16.6\%$$

Option (d) is right.