A, B, and C together can complete a work in 12 days. B and C together can complete the same work in 20 days. Find the time taken by A alone to complete the whole work (in days).
Let the total work (LCM of 20 and 12) = 60 units
Efficiency of A, B and C together = 60/12 = 5 units/day
Efficiency of B and C together = 60/20 = 3 units/day
Efficiency of A = 5 - 3 =2 units/day
Required time = 60/2 = 30 days
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