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UPPSC-LECTURER’21 EE: Daily Practices Quiz 13-Oct-2021

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UPPSC-LECTURER’21 EE:  Daily Practices Quiz

UPPSC-LECTURER’21 EE: Daily Practices Quiz 13-Oct-2021

Each question carries 3 marks.
Negative marking: 1 mark each or 1/3rd
Total Questions: 06
Time: 08 min.

Q1. The miller effect input capacitance CMi is
(a) (1-AV ) Cf
(b) (1-Cf ) AV
(c) (1-Cf^2 ) AV
(d) None of the above
Where; Cf=feedback capacitance

Q2. V being the voltage impressed on a dielectric, dielectric loss is proportional to
(a) V
(b) V^(-1)
(c) V^2
(d) V^(-2)

Q3. A 6-pole, 3-phase alternator running at 1000 rpm supplies to an 8-pole, 3-phase induction motor which has a rotor current of frequency 2 Hz. The speed at which the motor operates is
(a) 750 rpm
(b) 720 rpm
(c) 960 rpm
(d) 1000 rpm

Q4. In a common emitter configuration if β=100 and base current is 50 µA. Then the value of α is…………
(a) 0.88
(b) 0.99
(c) 0.89
(d) 0.9

Q5. In the bode-plot of a unity feedback control system, the value of phase of G(jω) at the gain cross-over frequency is -125⁰. The phase margin of the system is
(a) 55⁰
(b) -55⁰
(c) 125⁰
(d) -125⁰

Q6. Which of the following theorems can be applied to any network linear or non-linear, active or passive, time-variant or time-invariant?
(a) Norton theorem
(b) Thevenin theorem
(c) Superposition theorem
(d) Tellegen theorem

 

SOLUTIONS

S1. Ans.(a)
Sol. Input capacitance (Miller effect) CMi=(1-AV ) Cf

S2. Ans.(c)
Sol. Dielectric loss is given by, P=2πfCV^2 tan⁡δ .

S3. Ans.(b)
Sol. Supply frequency(f)=(1000×6)/120=50 Hz
Slip frequency: sf=2 (ACQ)
∴slip(s)=2/50=0.04
∴Ns=120f/P=(120×50)/8=750 rpm
∴Nr=Ns (1-s)=750×(1-0.04)=720 rpm

S4. Ans.(b)
Sol. α=β/(β+1)=100/101=0.99

S5. Ans.(a)
Sol. Phase margin is calculated at gain cross over frequency. At gain cross-over frequency, magnitude of G(jω) is 1.
phase of G(jω)=∠G(jω)=-125⁰
∴PM=180^0+∠G(jω)=180^0-125^0=55⁰

S6. Ans.(d)
Sol. Tellegen theorem can be applied to any network linear or non-linear, active or passive, time-variant or time-invariant.

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