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# UPPSC-LECTURER’21 EE: Daily Practices Quiz 04-Oct-2021

## UPPSC Technical Education Teaching Exam Notification 2021

Uttar Pradesh Public Service Commission has released the official notification for the recruitment of PrincipalLecturerLibrarian, and Workshop Superintendent. The Online application has been started on 15th September 2021 and the last date to apply online is 15th October 2021. The recruitment is for a total of 1370 UPPSC Polytechnic Lecturer Vacancies.

## UPPSC-LECTURER’21 EE:  Daily Practices Quiz

UPPSC-LECTURER’21 EE: Daily Practices Quiz 04-Oct-2021

Each question carries 3 marks.
Negative marking: 1 mark each or 1/3rd
Total Questions: 06
Time: 08 min.

Q1. The time-constant of the network shown in the figure is

(a) CR
(b) 2 CR
(c) CR/4
(d) CR/2

Q2. The signal is shown below in the figure represents?

(a) Energy signal
(b) Power signal
(c) Energy & power
(d) Neither energy nor power

Q3. For induction motors at low values of slip:
(a) The torque slip is approximately a hyperbola
(b) The torque slip is approximately a straight line
(c) The torque slip curve is at its maximum
(d) The torque slip is approximately a parabola

Q4. The minimum number of two-input NAND gates required to perform the two-input
OR gate?
(a) 1
(b) 3
(c) 2
(d) 4

Q5. Phase reversed of 180⁰ as compared to input occurs in the output of
(a) CE amplifier
(b) CB amplifier
(c) CC amplifier
(d) All of the above

Q6. A single phase, half-wave, controlled rectifier has 400 sin⁡〖(314 t)〗 as the input voltage and R as the load. For a firing angle of 60⁰ for the SCR, the average output voltage is
(a) 200/π
(b) 240/ π
(c) 300/ π
(d) 400/ π

## SOLUTIONS

S2. Ans.(d)
Sol. This is ramp signal, ramp signal is neither energy signal nor power signal.

S3. Ans.(b)
Sol. For induction motor –
T=(KS E₂²R₂)/(R₂²+(S×_2)²)
at low value of slip, S×_2≪R₂
⇒ T=(KSE₂²R₂)/(R₂²)
⇒ T∝S

S5. Ans.(a)
Sol. Phase reversed of 180⁰ as compared to input occurs in the output of CE amplifier.

S6. Ans.(c)
Sol. A single phase, half-wave, controlled rectifier, V_avg=V_m/2π(1+cos⁡〖α)〗
∵V_avg=400/2π(1+cos⁡〖60⁰)=(400×3)/(2π ×2)〗=300/π

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