Zakir travels from City A to City B. If Zakir drives his car at 2/3 of his normal speed, then he reaches City B 10 minutes late. Find the time (in minutes) that Zakir would have taken to travel from City A to City B if he drove at his normal speed.

Correct option is A

Given:

- If Zakir drives at 2/3 of his normal speed, he is 10 minutes late.

- Let the normal time taken to reach City B be x minutes.

Formula Used:

- Time =$$\frac{Distance }{ Speed}$$​

- If speed decreases, time increases proportionally for the same distance.

- Let normal time = x, then new time = ($$\frac{3}{2}$$​)x (because speed is $$\frac{2}{3}$$​ of normal)

- New time - Normal time = 10

Solution:

Let the time taken at normal speed be x minutes.

Then, time taken at $$\frac{2}{3}$$​ of the normal speed = ($$\frac{3}{2}$$​)x minutes.

According to the question:

​$$\left(\frac{3}{2}\right)x - x = 10 \\\ \\\Rightarrow \frac{3x - 2x}{2} = 10 \\\ \\\Rightarrow \frac{x}{2} = 10 \\\ \\\Rightarrow x = 20$$​​

Hence, Zakir would have taken 20 minutes to travel from City A to City B at normal speed.