Manoj travels from City A to City B. If Manoj drives his car at $$\frac{1}{5}$$​of his normal speed, then he reaches City B 36 minutes late. Find the time (in minutes) that Manoj would have taken to travel from City A to City B if he drove at his normal speed.

Manoj drives at 1/5 of his normal speed and reaches 36 minutes late.

Concept:
Speed and time are inversely proportional.

Solution:
If speed becomes 1/5, time becomes 5 times.

Let normal time = T

Slow speed time = 5T

Extra time = 5T − T = 4T

Given delay = 36 minutes

So,
4T = 36
T = 9

Answer: 9 minutes