Kamal travels from City A to City B. If Kamal drives his car at 1/4 of his normal speed, then he reaches City B 54 minutes late. Find the time (in minutes) that Kamal would have taken to travel from City A to City B if he drove at his normal speed.

Correct option is D

Given:

At $$\frac{1}{4}$$​ of his normal speed, Kamal is 54 minutes late.

Concept Used:

Time is inversely proportional to speed for a fixed distance.

Solution:

Let the normal time be t minutes

At $$\frac{1}{4}$$​ speed, the time taken is 4t

The difference in time is:

4t - t = 54

3t = 54

t = $$\frac{54}{3}$$​ = 18 minutes

Thus, the time Kamal would have taken to travel at his normal speed is 18 minutes.