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Arun travels from city A to City B. If Arun drives his cat at 2/3 rd of his normal speed, then he reaches City B 38 minutes late. Find the time (in mi
Question

Arun travels from city A to City B. If Arun drives his cat at 2/3 rd of his normal speed, then he reaches City B 38 minutes late. Find the time (in minutes) that Arun would have take to travel from City A to City B if he drove at his normal speed.

A.

76

B.

73

C.

81

D.

78

Correct option is A

Given:
New speed is 23\frac{2}{3}​ of normal speed.
Delay time = 38 minutes.
Formula Used:
Time = DistanceSpeed \frac{Distance}{Speed}​​
Solution:
Ratio of new speed to normal speed = 2 : 3
Ratio of new time to normal time = 3 : 2
Difference in time ratio = 3 - 2 = 1
1 unit corresponds to 38 minutes.
Normal time corresponds to 2 units.
Normal time = 2 × 38 = 76
Final Answer
So the correct answer is (a)

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