A car covers a certain distance in 8 hours at a uniform speed. If the speed of the car is increased by 5 km/hr, then the same distance could have been covered in 7 hours 30 minutes. What is the distance covered?

Correct option is B

Given:
Time 1 (T1) = 8 hours
Time 2 (T2) = 7 hours 30 mins = 7.5 hours
Speed difference = +5 km/hr
Formula Used:
​$$\text{Distance} = \text{Speed} \times \text{Time}$$​​
Solution:
Let the initial speed be S km/hr.
Distance in case 1: D = S$$\times 8$$​​
Distance in case 2: D = (S + 5) $$\times 7.5$$​​
Since distance is constant:
8S = 7.5(S + 5)
8S = 7.5S + 37.5
0.5S = 37.5
S = 75 km/hr
Calculate Distance:
D  $$= 8 \times 75 = 600 \text{ km}$$​​
So the correct answer is (b)