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X does half as much work as Y in 1/6 of time. If together they can complete a job in 10 days, how many days will Y take to complete it, when he works
Question

X does half as much work as Y in 1/6 of time. If together they can complete a job in 10 days, how many days will Y take to complete it, when he works alone?

A.

40 days

B.

30 days

C.

24 days

D.

35 days

Correct option is A

Given:
Worker X does half as much work as Y in 16\frac{1}{6}​​ of the time.
Together, X and Y can complete the job in 10 days. 
Formula Used: 
Total Work=Efficiency×Times\text{Total Work} = \text{Efficiency}\times \text{Times} 
Solution: 
X does half as much work as Y in 16\frac{1}{6}​ of the time. 
If Y's efficiency is 1 unit , then,
X"s efficiency is 3.
Now, Time taken together X + Y = 10 days
Total work = (1+3)×10=40 unit(1+3)\times 10 = 40 \,unit 
Time taken by Y to work alone,
Time = 401=40 days\frac{40}{1} = \bf 40 \, days ​

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