What is the remainder when $$58^{29}$$​ is divided by 5?

Correct option is B

Concept Used:

remainder of a number when it is divided by 5. 

Case1 when unit digit is less than 5 then unit digit is reminder.

Case2 when unit digit is greater than 5 then reminder = unit digit - 5.

Solution:

​$$58^{29}$$​ unit digit of it = 8

when 8 is unit digit of a number then unit digit of its power 1=8

when 8 is unit digit of a number then unit digit of its power 2=4

when 8 is unit digit of a number then unit digit of its power 3=2

when 8 is unit digit of a number then unit digit of its power 4=6

when 8 is unit digit of a number then unit digit of its power 5=8

So, this is shows that power of 8 unit digit repeat itself in every 4 times 

unit digit of ​$$58^{29}$$​=8

reminder when ​$$58^{29}$$ is divide by 5 =8-5

=3