If x+y+z=0, where none of x,y and z is equal to 0 , then find the value of $$\frac{x^2}{yz} + \frac{y^2}{zx} + \frac{z^2}{xy}$$​​

Correct option is A

Given
x + y + z = 0
x, y, z ≠ 0
Formula Used
If a + b + c = 0, then $$a^3 + b^3 + c^3 = 3abc$$​​
Solution
$$\frac{x^2}{yz} + \frac{y^2}{zx} + \frac{z^2}{xy}$$​​
= $$\frac{x^3 + y^3 + z^3}{xyz}$$​​
Since x + y + z = 0, we know that $$x^3 + y^3 + z^3 = 3xyz$$​​
Substitute this identity back into the expression:
​$$\frac{3xyz}{xyz} = 3$$​​
Final Answer
So the correct answer is (a)