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If a + b = 13 and a3+b3=559a^3+b^3=559 a3+b3=559​. Find the value of a2+b2.a^2+b^2 .a2+b2.​​
Question

If a + b = 13 and a3+b3=559a^3+b^3=559 ​. Find the value of a2+b2.a^2+b^2 .​​

A.

105

B.

85

C.

125

D.

95

Correct option is B

Given:
a + b = 13
a3+b3=559a^3 + b^3 = 559​​
Formula Used:
a3+b3=(a+b)(a2+b2ab)a^3 + b^3 = (a+b)(a^2 + b^2 - ab)​​
(a+b)2=a2+b2+2ab(a+b)^2 = a^2 + b^2 + 2ab​​
Solution:
Substitute the known values into the sum of cubes formula:
559=13(a2+b2ab)559 = 13(a^2 + b^2 - ab)​​
a2+b2ab=55913=43a^2 + b^2 - ab = \frac{559}{13} = 43​​
Substitute the known values into the square formula:
132=a2+b2+2ab13^2 = a^2 + b^2 + 2ab​​
169=a2+b2+2ab169 = a^2 + b^2 + 2ab​​
We now have two equations:
1)a2+b2ab a^2 + b^2 - ab​ = 43
2)a2+b2+2ab a^2 + b^2 + 2ab​ = 169
Subtract equation (1) from equation (2):
3ab = 169 - 43 = 126
ab = 42
Substitute the value of ab back into equation (1):
a2+b242=43a^2 + b^2 - 42 = 43​​
a2+b2a^2 + b^2 ​= 43 + 42 = 85
Final Answer
So the correct answer is (b)

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