The difference of squares of two consecutive odd numbers is 56. What is the sum of the two numbers?

Correct option is D

Given:
The difference of squares of two consecutive odd numbers is 56.
Formula Used:
​$$a^2 - b^2 = (a - b) × (a + b)$$​​
Solution:
Let the two consecutive odd numbers be x and x + 2.
$$(x + 2)^2 - x^2$$​ = 56
Apply the algebraic identity.
(x + 2 - x) × (x + 2 + x) = 56
2 × (2x + 2) = 56
2x + 2 = 28
The sum of the two numbers is exactly x + (x + 2) = 2x + 2.
Therefore, the sum of the two numbers is 28.
Final Answer
So the correct answer is (d)