The cost of a table exceeds that of a chair by ₹5,000. If the combined price of 16 tables and 14 chairs amounts to ₹2,00,000, determine by what percentage the price of a chair is less than the price of a table.

Correct option is D

Given:
Price of a table - Price of a chair = 5000
Combined price of 16 tables and 14 chairs = 200000
Formula Used:
Percentage Less = $$\frac{Difference}{Base Value}$$​ × 100
Solution:
Let the price of a chair be C and the price of a table be T.
T = C + 5000
16 × T + 14 × C = 200000
Substitute the value of T in the equation.
16 × (C + 5000) + 14 × C = 200000
16C + 80000 + 14C = 200000
30C = 120000
C = 4000
The price of a chair is 4000.
T = 4000 + 5000 = 9000
The price of a table is 9000.
Difference in price = 9000 - 4000 = 5000
Required percentage = $$\frac{5000}{9000}$$​ × 100

Required percentage = $$\frac{500}{9}$$​ = 55.56%
Final Answer
So the correct answer is (d)