Correct option is C
Given:2 pens+5 pencils=57Increase in cost of one pen=1.50Decrease in cost of one pencil=1New cost of 5 pens and 3 pencils=109Concept Used:Linear equations in two variablesFormula Used:ax+by=cSolution:Let cost of one pen=xLet cost of one pencil=y2x+5y=57(1)New cost of one pen=x+1.5New cost of one pencil=y−15(x+1.5)+3(y−1)=1095x+7.5+3y−3=1095x+3y=104.5(2)Multiply (1) by 3:6x+15y=171(3)Multiply (2) by 5:25x+15y=522.5(4)(4)−(3):19x=351.5x=18.5Substitute x in (1):2(18.5)+5y=5737+5y=57y=4Original cost of 3 pens and 4 pencils:3x+4y=3(18.5)+4(4)=55.5+16=71.5Final Answer:71.50