Correct option is B
Solution:
Let original cost of a pen = ₹p, pencil = ₹q
18p + 4q = 200
After change: pen → p - 1, pencil → q + 3
19(p-1) + 3(q+3) = 151
19p + 3q = 161
Multiply (1) by 3 and (2) by 4:
54p + 12q = 600
76p + 12q = 644
Subtract:
22p = 44
p = 2
Plug into 19p+3q=161:
38 + 3q = 161
3q = 123
q = 41
Original cost of 12 pens and 10 pencils:
12p + 10q = 12(2) + 10(41) = 24 + 410 = ₹434