What is the area of a triangle (in "$$cm^2$$​" ) having sides of length 24 cm, 17 cm and 9 cm?

Correct option is A

Given:

Sides of a triangle are 24cm,17cm and 9cm

Formula Used:

Area of triangle = $$\sqrt{s(s-a)(s-b)(s-c)}$$​​

​$$s= \frac{a+b+c}{2}$$​​

Where s is semi perimeter and a, b, c are sides of triangle

Solution:

We have sides as 24cm, 17cm and 9cm

​$$s= \frac{a+b+c}{2} = \frac{24+17+9}{2} = 25m$$​​

​$$Area = \sqrt {25(25-24)(25-17)(25-9)}$$​​

​$$= \sqrt {25(1)(8)(16)}$$​​

​$$= 40\sqrt{2}cm^2$$