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    Two trains of equal length are running on parallel lines in the same direction at speeds of 101 km/h and 29 km/h. The faster train passes the slower t
    Question

    Two trains of equal length are running on parallel lines in the same direction at speeds of 101 km/h and 29 km/h. The faster train passes the slower train in 21 seconds. The length of each train is:

    A.

    210 meters

    B.

    209 meters

    C.

    208 meters

    D.

    202 meters

    Correct option is A

    Given:

    Speed of the faster train = 101 km/h

    Speed of the slower train = 29 km/h

    Time taken for the faster train to pass the slower train = 21 seconds

    The length of both trains is equal.

    Formula Used:

    Distance = Speed × Time

    Solution:

    Relative speed = Speed of faster train - Speed of slower train

    Relative speed = 101 - 29 = 72 km/h

    Relative speed in m/s =72×10003600=20 m/s \frac{72 \times 1000}{3600} = 20 \, \text{m/s}

    Distance covered = 20×21=420 m0 \times 21 = 420 \, \text{m}

    The distance covered is the sum of the lengths of the two trains, and since the trains are of equal length, each train's length is:

    Length of each train =4202=210 m \frac{420}{2} = 210 \, \text{m}

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