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    Two trains are moving in opposite directions at speeds of 60 km/h and 50 km/h. The length of one train is 430 m. The time taken by them to cross each
    Question

    Two trains are moving in opposite directions at speeds of 60 km/h and 50 km/h. The length of one train is 430 m. The time taken by them to cross each other is 44 seconds. The length (in m) of the other train, correct to 2 decimal places, is:

    A.

    916.15

    B.

    914.44

    C.

    913.17

    D.

    912.67

    Correct option is B

    Given:

    Speed of train 1, v₁ = 60 km/h
    Speed of train 2, v₂ = 50 km/h
    Length of train 1, L₁ = 430 m
    Time taken to cross each other, t = 44 seconds
    Length of train 2, L₂ = ? 
    Formula Used:
    Relative speed when trains move in opposite directions: v₁ + v₂
    Distance covered when crossing each other = L₁ + L₂
    Time=DistanceSpeed\text{Time} = \frac{\text{Distance}}{\text{Speed}}​​
    Convert speeds from km/h to m/s:
    v (m/s)=v (km/h)×518v \, \text{(m/s)} = v \, \text{(km/h)} \times \frac{5}{18}\\​​
    Solution:
    Relative speed = (50+60)×518=110×518 m/s(50 + 60) \times \frac{5}{18} = 110 \times \frac{5}{18} \, \text{m/s}\\​​
    Distance covered in 44 seconds:
    Distance=Speed×Time=110×518×44=1344.4444 m\text{Distance} = \text{Speed} \times \text{Time} = 110 \times \frac{5}{18} \times 44 = 1344.4444 \, \text{m}\\​​
    L1+L2=1344.444L2=1344.444430=914.444 mL_1 + L_2 = 1344.444\\L_2 = 1344.444 - 430 = 914.444 \, \text{m}\\​​
    The length of the other train is 914.44 meters.

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