Three identical impedances are connected in delta. The load is supplied by a 3- phase supply of 300 V. The line current is 30√3A. Calculate the impedance per phase.

Correct option is D

$$\text{For delta-connected system:} \\[4pt]\bullet \; \text{Line voltage } V_L = V_p \\[4pt]\bullet \; \text{Phase current } I_p = \frac{I_L}{\sqrt{3}} \\[8pt]\text{Given:} \\[4pt]\bullet \; V_L = 300\,\text{V} \\[4pt]\bullet \; I_L = 30\sqrt{3}\,\text{A} \\[8pt]\textbf{Calculation:} \\[4pt]I_p = \frac{30\sqrt{3}}{\sqrt{3}} = 30\,\text{A} \\[6pt]Z = \frac{V_p}{I_p} = \frac{300}{30} = 10\,\Omega$$​​