Power loss and voltage drop respectively, in the 2Ω resistor is

Correct option is B

​$$\textbf{Given Circuit} \\[6pt]\bullet \ \text{Supply voltage } = 20 \text{ V} \\[4pt]\bullet \ \text{Resistors in series:} \\[2pt]\quad R_1 = 2 \, \Omega \\[2pt]\quad R_2 = 3 \, \Omega \\[12pt]\textbf{Step 1: Total Resistance} \\[6pt]R_{\text{total}} = 2 + 3 = 5 \, \Omega \\[12pt]\textbf{Step 2: Circuit Current} \\[6pt]I = \frac{V}{R_{\text{total}}} = \frac{20}{5} = 4 \text{ A} \\[12pt]\textbf{Step 3: Voltage Drop across } 2 \, \Omega \text{ Resistor} \\[6pt]V_{2\Omega} = I \times R = 4 \times 2 = 8 \text{ V} \\[12pt]\textbf{Step 4: Power Loss in } 2 \, \Omega \text{ Resistor} \\[6pt]P_{2\Omega} = I^2 R = (4)^2 \times 2 = 32 \text{ W}$$​​