What is the total number of electrons that pass through a conductor in 2 s, if the current through it is 80 mA?

Correct option is A

​$$\text{Electric current is the rate of flow of charge:} \\[6pt]I = \frac{Q}{t} \ \Rightarrow \ Q = I \times t \\[12pt]\textbf{Given:} \\[6pt]\bullet \ \text{Current } I = 80 \text{ mA } = 0.08 \text{ A} \\[4pt]\bullet \ \text{Time } t = 2 \text{ s} \\[12pt]\textbf{Charge passed:} \\[8pt]Q = 0.08 \times 2 = 0.16 \text{ C} \\[14pt]\text{The charge of one electron is:} \\[8pt]e = 1.6 \times 10^{-19} \text{ C} \\[14pt]\textbf{Number of electrons:} \\[8pt]n = \frac{Q}{e} = \frac{0.16}{1.6 \times 10^{-19}} = 10^{18}$$​​