A 4Ω resistor has a specified maximum power dissipation of 784 W. Calculate its maximum current level.

Correct option is C

To calculate the maximum current level for a 4Ω resistor with a maximum power dissipation of 784 W, we can use the formula for power dissipation in a resistor:

​$$P = I^2 R \\[8pt]\text{Where:} \\[4pt]\bullet \; P \text{ is the power dissipation (784 W),} \\[4pt]\bullet \; I \text{ is the current (which we need to find),} \\[4pt]\bullet \; R \text{ is the resistance (4}\Omega\text{).} \\[8pt]\text{Rearranging the formula to solve for } I: \\[4pt]I = \sqrt{\frac{P}{R}} \\[8pt]\text{Now, substituting the known values:} \\[4pt]I = \sqrt{\frac{784}{4}} = \sqrt{196} = 14\,A \\[8pt]\text{Thus, the maximum current is } 14\,A.$$​​