Three equations are given below. Solve the equations and answer the question given below.
A: x² + x – 6 = 0
B: y² + y -12 = 0
C: 2z² - 3z – 5 = 0

Find the relation between I, II and II. (Consider only positive roots of equations A, B and C.)

Correct option is C

A: x² + x – 6 = 0
x² + 3x - 2x – 6 = 0
x = -3, 2
x = 2
B: y² + y -12 = 0
y² + 4y – 3y -12 = 0
y = -4, 3
y =3
C: 2z² - 3z – 5 = 0
2z² - 5z + 2z – 5 = 0
z = 2.5, -1
z = 2.5

III: 12Z
12(2.5) = 30
So, I < II > III