Correct option is A
I. 6x2 – 4x – 3x + 2 = 0
2x(3x-2) – 1(3x -2) = 0
(2x -1) (3x -2) = 0
x = 0.5 & 0.66
II. 10y2 – 6y – 5y + 3 = 0
2y(5y -3) – 1(5y -3) = 0
(2y – 1) (5y-3) = 0
y = 0.5 & 0.60
| x | y | Relation |
| 0.5 | 0.5 | y = x |
| 0.5 | 0.60 | y > x |
| 0.66 | 0.5 | x > y |
| 0.66 | 0.6 | x > y |
So, no relation can be established