In each question two equations number (I) and (II) are given. You should solve both the equations and mark appropriate answer.

I. $$x^2 - 10x + 24 = 0$$​​
II. $$5y^2 - 16y + 12 = 0$$​​

Correct option is A

I. x² -6x - 4x + 24 = 0

x(x-6) - 4(x-6) = 0

(x-4) (x-6) =0

x = 4 & 6

II. 5y²​ -10y - 6y + 12 = 0

5y(y-2) - 6(y-2)=0

(5y -6) (y-2) = 0

y = 6/5 & 2

y = 1.2 & 2

So, x>y