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I: x(x−5)+20x=9−x\frac{x(x-5)+20}{x}=9 -xxx(x−5)+20​=9−x​​II: y² + 2√17 y - 5² = √68 y
Question

I: x(x5)+20x=9x\frac{x(x-5)+20}{x}=9 -x​​

II: y² + 2√17 y - 5² = √68 y

A.

If x > y

B.

If x ≥ y

C.

If x < y

D.

If x ≤ y

E.

If x = y or no relation can be established between x and y

Correct option is E

I: x(x5)+20x=9x\frac{x(x-5)+20}{x}=9 -x

x² - 5x + 20 = 9x - x²
2x² - 14x + 20 = 0
x² - 7x + 10 = 0
x² - 2x – 5x + 10 = 0
x = 2, 5
II: y² + 2√17 y - 5² = √68 y
y² + 2√17 y - 5² = 2√17 y
y² = 25
y = 5, -5
So, no relation can be established between x and y

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