Correct option is C
I. 2x2 - 4x - 5x + 10 = 0
2x(x-2) - 5(x-2) = 0
(2x-5) (x-2) =0
x = 5/2 & 2
x = 2.5 & 2
II. y2 - 7y - 5y + 35 = 0
y(y-7) - 5(y-7) = 0
(y-7) (y-5) = 0
y = 7 & 5
| x | y | Relation |
| 2.5 | 7 | y > x |
| 2.5 | 5 | y > x |
| 2 | 7 | y > x |
| 2 | 5 | y > x |
So, x<y