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    ​I. 2x2 + 19x + 42 = 0​II. 2y2 + 7y + 5 = 0
    Question

    In each question two equations number (I) and (II) are given. You should solve both the equations and mark appropriate answer.


    I. 2x2 + 19x + 42 = 0

    II. 2y2 + 7y + 5 = 0

    A.

    If x=y or no relation can be established

    B.

    If x>y

    C.

    If x<y

    D.

    If x≥y

    E.

    If x≤y

    Correct option is C

    I. 2x2 + 12y + 7y + 42 = 0

    2x(x+6) + 7(y+6) = 0

    (2x+7) (y+6) = 0

    x = - 3.5 & - 6

    II. 2y2 + 2y + 5y + 5 = 0

    2y(y+1) +5(y+1) = 0

    (2y+5) + (y+1) =0

    y =-

    & -1

    x

    y

    Relation

    -3.5

    -2.5

    y > x

    -3.5

    - 1

    y > x

    -6

    -2.5

    y > x

    -6

    -1

    y > x

    So, x<y

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