Correct option is C
I. 2x2 + 12y + 7y + 42 = 0
2x(x+6) + 7(y+6) = 0
(2x+7) (y+6) = 0
x = - 3.5 & - 6
II. 2y2 + 2y + 5y + 5 = 0
2y(y+1) +5(y+1) = 0
(2y+5) + (y+1) =0
y =-

& -1
| x | y | Relation |
| -3.5 | -2.5 | y > x |
| -3.5 | - 1 | y > x |
| -6 | -2.5 | y > x |
| -6 | -1 | y > x |
So, x<y