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​I. 2x2 + 19x + 42 = 0​II. 2y2 + 7y + 5 = 0
Question

In each question two equations number (I) and (II) are given. You should solve both the equations and mark appropriate answer.


I. 2x2 + 19x + 42 = 0

II. 2y2 + 7y + 5 = 0

A.

If x=y or no relation can be established

B.

If x>y

C.

If x<y

D.

If x≥y

E.

If x≤y

Correct option is C

I. 2x2 + 12y + 7y + 42 = 0

2x(x+6) + 7(y+6) = 0

(2x+7) (y+6) = 0

x = - 3.5 & - 6

II. 2y2 + 2y + 5y + 5 = 0

2y(y+1) +5(y+1) = 0

(2y+5) + (y+1) =0

y =-

& -1

x

y

Relation

-3.5

-2.5

y > x

-3.5

- 1

y > x

-6

-2.5

y > x

-6

-1

y > x

So, x<y

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