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The value of 0.34−0.240.32+0.22\frac{{0.3}^4-{0.2}^4}{{0.3}^2+{0.2}^2}0.32+0.220.34−0.24​​ is:
Question

The value of 0.340.240.32+0.22\frac{{0.3}^4-{0.2}^4}{{0.3}^2+{0.2}^2}​ is:

A.

0.05

B.

0.15

C.

0.51

D.

0.5

Correct option is A

Given:

0.340.240.32+0.22\frac{0.3^4 - 0.2^4}{0.3^2 + 0.2^2}

Formula Used:

a4b4=(a2b2)(a2+b2)a^4 - b^4 = (a^2 - b^2)(a^2 + b^2)

Solution:

(0.320.22)(0.32+0.22)0.32+0.22\frac{(0.3^2 - 0.2^2)(0.3^2 + 0.2^2)}{0.3^2 + 0.2^2}

= 0.09 - 0.04 = 0.05

Thus, the value of the expression is 0.05.

Alternate Method:

0.340.240.32+0.22\frac{0.3^4 - 0.2^4}{0.3^2 + 0.2^2}​​

=0.00810.00160.09+0.04=\frac{0.0081 - 0.0016}{0.09 + 0.04}

=0.00650.13=0.05=\frac{0.0065}{0.13} = 0.05

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