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    The solution of 1x−2<0\frac{1}{x-2} < 0x−21​<0​ is :
    Question

    The solution of 1x2<0\frac{1}{x-2} < 0​ is :

    A.

    xϵ(,2)x \epsilon (-\infin , 2)​​

    B.

    xϵ(,2)x \epsilon (-\infin , -2)​​

    C.

    xϵ(2,)x \epsilon (2 , \infin)​​

    D.

    xϵ(2,)x \epsilon (-2 , \infin)​​

    Correct option is A

    Given:

    1x2<0\frac{1}{x-2} < 0

    Solution:

    The expression 1x2\frac{1}{x - 2} will be negative,

    Since the numerator is positive (1 > 0)

    When the denominator (x - 2) is negative, the numerator is always positive (1).

    The denominator is negative when x - 2 < 0, or equivalently, x < 2.

    However, we must exclude x=2 because the denominator would be zero, which is undefined.

    The solution to the inequality is x ∈ (−∞,2).

    Lets check by options;

    Option (a): xϵ(−∞,2)

    This matches our solution.

    Option (b): xϵ(−∞,−2)​​

    This means x<−2, which is not the solution.

    Option (c): xϵ(2,∞)​​

    This means x>2, which would make the fraction positive.

    Option (d): xϵ(−2,∞)

    This means x>−2, which includes values greater than 2, making the fraction positive.

    Thus, the correct answer is (a).

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