The points A, B and C lie on a circle with centre O. The ∠ACB = 47.5°. What is the ∠AOB on the minor $$\widehat{AB}$$​?

Correct option is B

​Given:

​$$ACB = 47.5^\circ$$​​

A, B, C are on the circle with center O.

Formula Used:
The angle subtended at the center is twice the angle subtended at the circumference:

​$$\angle AOB = 2 \times \angle ACB$$ 

Solution:

Using the property: 

​$$\angle AOB = 2 \times 47.5^\circ = 95^\circ$$​​