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    Five concentric, adjacent, semi-circular running tracks, each of mean length 100 m and width 2.5 m are marked on a field. If the angle subtended by in
    Question

    Five concentric, adjacent, semi-circular running tracks, each of mean length 100 m and width 2.5 m are marked on a field. If the angle subtended by inner track is 1.00 rad, the angle subtended by the outermost track is

    A.

    0.90 rad

    B.

    0.91 rad

    C.

    0.88 rad

    D.

    0.98 rad

    Correct option is B

    Given:

    Five adjacent semi-circular tracks.
    Each track has mean length = 100 meters.
    Width of each track = 2.5 meters.
    Inner track subtends an angle = 1.00 rad.

    Solution:

    Now Step-by-step:
    Step 1: Find the mean radius of the inner track.
    Mean length = Angle × Mean radius
    => 100 = 1.00 × r
    => r = 100 meters
    So, mean radius of inner track = 100 meters.
    Step 2: Find the mean radius of the outermost track.
    Total number of tracks = 5
    Each track has width = 2.5 m
    So, the outermost track is 4 widths away from the inner track.
    Thus,
    Extra radius = 4 × 2.5 = 10 meters
    Mean radius of outermost track = 100 + 10 = 110 meters.
    Step 3: Now find angle subtended by the outermost track.
    Again use:
    Mean length = Angle × Mean radius
    Thus,
    100 = Angle × 110
    Angle = 100/110
    Angle = 0.909 rad
    Now 0.909 is approximately 0.91 rad.

    Therefore, Option (b) 0.91 rad is the correct answer.

    Short Trick:
    When radius increases and arc length is fixed,
    New Angle = (Old Radius / New Radius) × Old Angle

    Here:
    New Angle = (100/110) × 1.00 = 0.909 ≈ 0.91 rad.


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