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The lengths of three medians of a triangle are 3 cm, 6 cm and 5 cm. The area of the triangle is :
Question

The lengths of three medians of a triangle are 3 cm, 6 cm and 5 cm. The area of the triangle is :

A.

4053 cm2\frac{\sqrt{405}}{3}\space\text{cm}^2​​

B.

3453 cm2\frac{\sqrt{345}}{3}\space\text{cm}^2​​

C.

43 56 cm2\frac{4}{3}\space\sqrt{56}\space\text{cm}^2​​

D.

2553 cm2\frac{\sqrt{255}}{3}\space\text{cm}^2​​

Correct option is C

Given:

Lengths of the medians: m1 = 3 cm, m2 = 6 cm, m3 = 5 cm

Formula Used:

Area of a triangle = 43sm(smm1)(smm2)(smm3) \frac{4}{3} \sqrt{s_m(s_m - m_1)(s_m - m_2)(s_m - m_3)}​​

where sm=m1+m2+m32s_m = \frac{m_1 + m_2 + m_3}{2}​ is the semi-perimeter of the medians.

Solution:

Semiperimeter sm=3+6+52=142=7 cm s_m = \frac{3 + 6 + 5}{2} = \frac{14}{2} = 7 \text{ cm}​​

Now,

Area = 437(73)(76)(75)\frac{4}{3} \sqrt{7(7 - 3)(7 - 6)(7 - 5)}​​

=437×4×1×2= \frac{4}{3} \sqrt{7 \times 4 \times 1 \times 2}​​

=4356 cm2= \frac{4}{3} \sqrt{56} \ \text{cm}^2​​

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