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    The lengths of three medians of a triangle are 3 cm, 6 cm and 5 cm. The area of the triangle is :
    Question

    The lengths of three medians of a triangle are 3 cm, 6 cm and 5 cm. The area of the triangle is :

    A.

    4053 cm2\frac{\sqrt{405}}{3}\space\text{cm}^2​​

    B.

    3453 cm2\frac{\sqrt{345}}{3}\space\text{cm}^2​​

    C.

    43 56 cm2\frac{4}{3}\space\sqrt{56}\space\text{cm}^2​​

    D.

    2553 cm2\frac{\sqrt{255}}{3}\space\text{cm}^2​​

    Correct option is C

    Given:

    Lengths of the medians: m1 = 3 cm, m2 = 6 cm, m3 = 5 cm

    Formula Used:

    Area of a triangle = 43sm(smm1)(smm2)(smm3) \frac{4}{3} \sqrt{s_m(s_m - m_1)(s_m - m_2)(s_m - m_3)}​​

    where sm=m1+m2+m32s_m = \frac{m_1 + m_2 + m_3}{2}​ is the semi-perimeter of the medians.

    Solution:

    Semiperimeter sm=3+6+52=142=7 cm s_m = \frac{3 + 6 + 5}{2} = \frac{14}{2} = 7 \text{ cm}​​

    Now,

    Area = 437(73)(76)(75)\frac{4}{3} \sqrt{7(7 - 3)(7 - 6)(7 - 5)}​​

    =437×4×1×2= \frac{4}{3} \sqrt{7 \times 4 \times 1 \times 2}​​

    =4356 cm2= \frac{4}{3} \sqrt{56} \ \text{cm}^2​​

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