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    The length of a rectangular plot is 10 meters more than its breadth. If the cost of fencing around the plot is ₹ 1,550 at the rate of ₹15.50 per meter
    Question



    The length of a rectangular plot is 10 meters more than its breadth. If the cost of fencing around the plot is ₹ 1,550 at the rate of ₹15.50 per meter, then the length of the plot will be

    A.

    20 meters

    B.

    30 meters

    C.

    40 meters

    D.

    10 meters

    Correct option is B

    Solution:Let the breadth of the rectangle be x meters.Then the length is x+10 meters.Perimeter of rectangle:P=2(l+b)=2(x+10+x)=2(2x+10)=4x+20Cost of fencing per meter = ₹15.50Total cost = ₹1,550Total length of fencing:155015.5=100 metersSo, 4x+20=100=>4x=80=>x=20Length = x+10=20+10=30 metersThe correct answer is: (b) 30 meters\textbf{Solution:} \\[5pt]\text{Let the breadth of the rectangle be } x \text{ meters.} \\\text{Then the length is } x + 10 \text{ meters.} \\[5pt]\text{Perimeter of rectangle:} \\P = 2(l + b) = 2(x + 10 + x) = 2(2x + 10) = 4x + 20 \\[5pt]\text{Cost of fencing per meter = ₹15.50} \\\text{Total cost = ₹1,550} \\[5pt]\text{Total length of fencing:} \\\frac{1550}{15.5} = 100 \text{ meters} \\[5pt]\text{So, } 4x + 20 = 100 \Rightarrow 4x = 80 \Rightarrow x = 20 \\[5pt]\text{Length = } x + 10 = 20 + 10 = 30 \text{ meters} \\[10pt]\boxed{\text{The correct answer is: (b) 30 meters}}​​

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