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    A square park has an area equal to the area of a rectangle whose length exceeds its breadth by 9 m and the breadth is half the side of the square. Fin
    Question

    A square park has an area equal to the area of a rectangle whose length exceeds its breadth by 9 m and the breadth is half the side of the square. Find the side of the square.

    A.

    6 m

    B.

    3 m

    C.

    5 m

    D.

    2 m

    Correct option is A

    Given:
    Area of square = Area of rectangle
    Length of rectangle = Breadth + 9 m
    Breadth of rectangle = Half of the side of the square
    Formula Used:
    Area of a square = side × side
    Area of a rectangle = length × breadth
    Solution:
    Let a be the side of the square.
    Express the breadth of the rectangle in terms of a:
    b = a2 \frac{a}{2}​​
    Express the length of the rectangle in terms of a:
    l = a2\frac{a}{2}​ + 9
    Set the area of the square equal to the area of the rectangle:
    a2=a2×(a2+9)a^2 = \frac{a}{2} × (\frac{a}{2} + 9)​​
    Expand the right side:
    a2=a24+9a2a^2 = \frac{a^2}{4} + \frac{9a}{2}​​
    Subtract the squared fraction from both sides:
    3a24=9a2\frac{3a^2}{4} = \frac{9a}{2}​​
    3a4=92\frac{3a}{4} = \frac{9}{2}​​
    3a = 18
    a = 6
    Final Answer
    So the correct answer is (a)

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